Contractor Exam Prep Classes
Contractor tests in Florida openbook and timed, so you will need to know how to find information and solve math problems within minutes, passing is difficult but you don't have to do it alone. Let us help you pass your contractor exams quickly so you can get back to running your business. Our classes teach you how to do two things: (1) Find information within the books and (2) Solve math problems. You can start taking classes as early as today! You can take these classes Online as well as InPerson in Tampa, Orlando, Fort Myers, and Fort Lauderdale.
Practice Questions
Let's see how you match up against some typical test questions! Read each question carefully and select the best option, then click on "Submit" to get the right answer as well as an explanation of how to solve it! If you don't do so well, don't worry, just sign up and start preparing for your exam within minutes.
Well Done! Current ratio is equal to current assets divided by current liabilities. The key to answering this question correctly is to differentiate between current and fixed assets, as well as between current and longterm liabilities. Inventory and Cash (checking account is the same as cash) add up to $111,000 ($111,000 comes from adding $25,000 and $86,000). Payroll taxes payable is the only current liability listed and is equal to $18,000. When we divide $111,000 by $18,000 we get 6.17, which is our current ratio. b) is the right answer.
Sorry, that's incorrect. Here is why: Current ratio is equal to current assets divided by current liabilities. The key to answering this question correctly is to differentiate between current and fixed assets, as well as between current and longterm liabilities. Inventory and Cash (checking account is the same as cash) add up to $111,000 ($111,000 comes from adding $25,000 and $86,000). Payroll taxes payable is the only current liability listed and is equal to $18,000. When we divide $111,000 by $18,000 we get 6.17, which is our current ratio. b) is the right answer.
Well Done! The sides of a square measuring 1,600 sf must be 40' long (40' x 40' equals 1,600 sf).  From the center for the end of the gable, there are 20' (half of 40').  Since the roof is at 45degrees (1:1 slope), the ridge (topcenter of the roof) rises to 20'.  The distance from the ridge to the edge can be calculated using Pythagorean Theorem C^2 = a^2 + b^2  C^2 = 20^2 + 20^2  C^2 = 400 + 400  C = Square root of 800  The distance between ridge and edge is 28.28'.  This multiplied by 40' give you the area of half of the roof (1131.20 sf), which multiplied times two gives you to total area (2,262.40 sf). 2,262.40 sf/100 sf per roofing square = 23 roofing squares. a) is the right answer.
Sorry, that's incorrect. Here is why: The sides of a square measuring 1,600 sf must be 40' long (40' x 40' equals 1,600 sf).  From the center for the end of the gable, there are 20' (half of 40').  Since the roof is at 45degrees (1:1 slope), the ridge (topcenter of the roof) rises to 20'.  The distance from the ridge to the edge can be calculated using Pythagorean Theorem C^2 = a^2 + b^2  C^2 = 20^2 + 20^2  C^2 = 400 + 400  C = Square root of 800  The distance between ridge and edge is 28.28'.  This multiplied by 40' give you the area of half of the roof (1131.20 sf), which multiplied times two gives you to total area (2,262.40 sf). 2,262.40 sf/100 sf per roofing square = 23 roofing squares. a) is the right answer.
Well Done! The bottom of the excavation is 40’ by 50’.  As you go up to the surface from the bottom of the excavation the walls will slope outward for 10’ at a 1:1 slope, which means that each wall will be 10 feet out at surface level.  Therefore, the top of the excavation will measure 60’ by 70’.  Since we now have two sets of dimensions we must find the average between them.  The average between 70’ and 50’ is 60’ and the average between 60’ and 40’ is 50’.  So now, we simply multiply 50’ times 60’ times 10’ (10 is still the depth) and we come up with our volume of 30,000 cf, but since the question is asking for cubic yards, we must divide the answer by 27 (there are 27 cubic feet in one cubic yard). d) is the right answer.
Sorry, that's incorrect. Here is why: The bottom of the excavation is 40’ by 50’.  As you go up to the surface from the bottom of the excavation the walls will slope outward for 10’ at a 1:1 slope, which means that each wall will be 10 feet out at surface level.  Therefore, the top of the excavation will measure 60’ by 70’.  Since we now have two sets of dimensions we must find the average between them.  The average between 70’ and 50’ is 60’ and the average between 60’ and 40’ is 50’.  So now, we simply multiply 50’ times 60’ times 10’ (10 is still the depth) and we come up with our volume of 30,000 cf, but since the question is asking for cubic yards, we must divide the answer by 27 (there are 27 cubic feet in one cubic yard). d) is the right answer.
Well Done! The average pool depth must be found by adding the shallow and deep ends together and dividing by 2, as follows: (3' + 8')/2 = 5.5'  Once the average depth is found, the volume can be calculated by multiplying the length, width and depth times each other, as follows: Pool volume = 12' x 20' x 5.5' = 1,320 cf  Once the volume is obtained, it must be converted to the appropriate number of gallons, as follows: 1,320 cf x 7.48 gallons per cf = 9,874 gallons. c) is the right answer.
Sorry, that's incorrect. Here is why: The average pool depth must be found by adding the shallow and deep ends together and dividing by 2, as follows: (3' + 8')/2 = 5.5'  Once the average depth is found, the volume can be calculated by multiplying the length, width and depth times each other, as follows: Pool volume = 12' x 20' x 5.5' = 1,320 cf  Once the volume is obtained, it must be converted to the appropriate number of gallons, as follows: 1,320 cf x 7.48 gallons per cf = 9,874 gallons. c) is the right answer.
Lecture Videos
When preparing for a test not all subjects share the same level of difficulty. Some subjects are considerably more difficult than others, specially those which relate to performing specific calculations. Our instructors create hundreds of videos explaining how to solve different types of problems and explaining different subjects, specially those which are a bit difficult for most students. Below is a sample video covering a blowcount calculation for pile driving. This video is kindly shared by one of our instructors teaching a General Engineering class. Please note this is meant to be a sample and will most likely not be part of the subjects covered by your particular exam.
Signing Up and Getting Started
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Click on the 'Contractor Licenses' on the main menu (above).

Select the license you need (if you cannot find the right license or have questions, just give us a call and we'll find it for you).

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Put in said ID and Password on our eCampus page (contractorEcampus.com)See first image below.

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If you wish to go to any of our inperson review classes, simply visit our ReviewClasses Schedule and follow the instructionsthey are free to all our students!