Design and construction of pile foundations

The design of pile foundations consists of two general steps: (1) the selection and design of the piles and driving equipment to be used and (2) the study of the soils to which the loads are transmitted. Allowable bearing strengths for soils vary from 1 T/sq ft (95 kN/m2) for clay to approximately 30 T/sq ft (2,900 kN/m2) for granite bedrock.

Average compression bearing values for gravel soils range from 5 to 6 T/sq ft (450 to 575 kN/sq m). The bearing resistance of a pile is, therefore, proportional to its size and the resistance of the soil in which it is driven.

Demonstration exercise

A 55-foot pile of lumber that has an average diameter of 16 inches. And a tip diameter of 12 in. It is introduced into soil that has an allowable load capacity of 6 T/sq ft and a shear strength of 700 lb/sq ft. Determine the safe load of the pile assuming the top 6 feet do not support any load due to unstable ground conditions.

Answer :

Final area = ((π x D2) ÷ (4))

The diameter of the tip of the pile in feet = 12 ÷ 16 = 0.75 foot

Final area = ((3.1415 x 0.752) ÷ (4)) = 0.44 square foot

Final load capacity = 6 x 2,000 x 0.44 = 5,280 lb

Soil shear capacity = soil shear strength x effective pile surface area

Effective pile surface area = effective pile length x average circumference

The average pile circumstance in feet = π x D
= 3.1415 x (16 ÷ 16) = 3.1415 feet

The effective length of the pile in feet = 55 - 6 = 49 feet

Effective Pile Surface Area = 49 x 3.1415 = 153,9335

Soil cutting capacity = 700 x 153.93 = 107.751 lb

Total pile capacity = 2,800 + 107.751 = 110.551 lb

Learning exercise

A 10.7 m pile of wood having an average diameter of 300 mm and a tip diameter of 200 mm is driven into soil that has an allowable load capacity of 380 kN/m2 and a shear strength of 33.5 kN/m2. Determine the safe carrying load of the pile assuming that the top 2 m will not support any load due to unstable ground conditions.

Answer :

Final area = ((π x D2) ÷ (4))

The diameter of the tip of the pile in meters = 200 ÷ 1,000 = 0.2 m

Final area = ((3.1415 x 0.22) ÷ (4)) = 0.03 m2

Final load capacity = 380 = 0.03 = 11.4 KN

Soil shear capacity = soil shear strength x effective pile surface area

Effective Pile Surface Area = effective pile length x average circumference

The average pile circumstance in feet = π x D
= 3.1415 x (300 ÷ 1,000) = 0.94 m

The effective length of the pile in meters = 10.7 - 2 = 8.7 m

Effective pile surface area = 8.7 x 0.94 = 8.2 square meters

Soil cutting capacity = 8.2 x 33.5 = 274.7 KN

Total pile capacity = 11.4 + 274.7 = 286 KN

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